WEBVTT
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to deter a mind The magnitude of the gravitational force
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on the moon we have to determine first war is
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the gravitational force that the sun exerts on the moon
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on. Then what is the reputational force that the
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earth exerts on the moon? We will begin the
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completing their force that the sun exerts on the moon
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F S m We can conflict that force by using
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the following equation as M is the gravitational force,
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then it is a cost to G times the mass
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off the sun times the mass off the moon divided
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by the distance between the centre off the sun on
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the center, off the moon squared. And that
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distance is R S M, which is close to
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1.5 times 10 to the 11. 71.5 banks 10
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to 11 squared now plaguing the other values that were
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given by the problem We get f S M as
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being equals to 6.6 to 7 Time stands for buying
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is 11 times 1.99 times. Stand to the authority
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times The mass off the moon, which is 7.35
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time stand to 22 and this is divided by 1.5
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times. Stand to the 11 squared and this gives
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us a gravitational force off a magnitude of approximately four
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0.34 times. Stand to the 20 new tones.
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Now we proceed to companies the magnitude of the gravitational
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force exerted on the moon by the earth. We
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do so by calculating F e M. It's very
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similar to what we had just don't want. The
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only thing that changes is that now we will use
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the earth Mass and the distance between the centre off
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the earth and the center off the room So we
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have F e m is equals to the neutrons.
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Constant times the mass off the earth times the mass
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off the moon, divided by the distance between the
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center of the earth in the center of the book
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squared by plugging the values that were given by the
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problem, we got 6.67 times stand to minus 11
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times the mask off the earth off 5.98 times.
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Stand to 24 kilograms and the mast off the moon
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off 7.35 times. Stand to 22 and this is
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divided by the distance between the centre off the earth
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and the center off the boom, which is tree
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0.85 times. Stand to the eight squared and this
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gives us gravitational force off the magnitude of approximately 1.98
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times. Stand to the 20 new terms. Now
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, let me organize the board to finish the question
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. Okay. Now, to finish the question,
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we must calculate what is the magnitude of the resulting
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gravitational force of the moon That resulting gravitational force results
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from the addition off F as m and F e
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m. Note that we are ardent factors. So
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we have to use the Gregorian theory, um,
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to get the magnitude off the resulting force so the
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resulting force I will call f it's equals to the
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square it off f S m squared plus f e
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m squared. Why is that? Because we are
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adding F S m with F e m and these
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results in the force that points in this direction and
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we have a rectangle triangle and then we just have
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to apply the Ivorian fuel him to get the value
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off f By plugging the values that we have.
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We got that f is it close to the square
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it off 4.34 Find stand to the 20 squared plus
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1.98 times, then to the 20 squared. And
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this gives the resulting gravitational force with a magnitude of
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approximately four 0.77 time stand to the 20 new stones
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.