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Okay, So in this problem we have I got
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Lillian telescope. And in the first itin off the
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problem, we want to calculate the focal eyepiece lens
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over the stethoscope, knowing that he has a magnification
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off for off four and a focal objective. Lend
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off one point 25 meters. Okay, So,
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first of all, we know that the total magnification
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is just the f objective divided by the the focal
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lens off the eyepiece. But since the leading telescope
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is constrict with are converging lens and a convex lens
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, we have a minor sign in front of the
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magnification. So to calculate the focal, I've piece
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that we want to discover it's just going to be
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minus for times one point actually divided. We have
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the miners f objective, divided by magnification. So
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this is just going to be minus one point 25
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divided by four. This is equals two minus 31
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. See question miners 31 point three. State team
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enters. Okay, so the second item off the
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problem, we went to discover Ah, the barrel
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lens off the telescope. And we know by definition
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that the barrel length is just the objective. Plus
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the eyepiece. Focal ends some. So this is
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just one point 25 minus zero point 31. This
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is just, let's see one point 56 meters and
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that's your final answer. So this problem. Thanks
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for watching.