WEBVTT
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00:00:00.840 --> 00:00:08.449 A:middle L:90%
So here we have one plus co sign Tha Tha
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00:00:09.240 --> 00:00:18.320 A:middle L:90%
uh divided by yeah 1- Coastline Data. So
3
00:00:18.329 --> 00:00:22.730 A:middle L:90%
we know that code sign pi equals negative one.
4
00:00:22.739 --> 00:00:24.699 A:middle L:90%
And we're trying to find the limit as X.
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00:00:24.699 --> 00:00:27.160 A:middle L:90%
Goes to pie or a state it goes to pie
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00:00:28.239 --> 00:00:30.460 A:middle L:90%
. So we see in this case we would get
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00:00:30.469 --> 00:00:35.689 A:middle L:90%
coastline of pie and co sign of pie I would
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00:00:35.689 --> 00:00:37.609 A:middle L:90%
just give us zero. So we don't even have
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00:00:37.609 --> 00:00:40.090 A:middle L:90%
to use the hotel's role in this case. So
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00:00:40.090 --> 00:00:42.939 A:middle L:90%
it's not necessary. In fact we shouldn't because we
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00:00:42.939 --> 00:00:47.390 A:middle L:90%
don't have an indeterminate form. So based on this
12
00:00:47.399 --> 00:00:50.000 A:middle L:90%
we can just plug in pi and we will get
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00:00:50.000 --> 00:00:53.369 A:middle L:90%
zero as the final answer. In other cases we
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00:00:53.369 --> 00:00:56.520 A:middle L:90%
might get in a determinant form such as this.
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00:00:56.530 --> 00:00:59.039 A:middle L:90%
Um in which case we would use the hotel's role
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00:00:59.049 --> 00:01:00.500 A:middle L:90%
but it's not necessary to use it here. Because
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00:01:00.509 --> 00:01:03.870 A:middle L:90%
when we take the limit as data goes to pi
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00:01:03.879 --> 00:01:07.590 A:middle L:90%
we end up getting zero as our final answer.
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00:01:07.599 --> 00:01:10.560 A:middle L:90%
So that will be our final answer in this case
20
--> A:middle L:90%
.