WEBVTT
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for part A were asked to figure out the maximum
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induced voltage in the coil when the number of turns
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is 1000 and the magnetic field perpendicular to the axis
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of rotation is point to Tesla. We're told that
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the area is 0.1 meter squared and it's rotating at
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60 revolutions per second, which converted to radiance by
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multiplying by two. Pi is 376.8 radiance per second
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. Okay, so the induced voltage will indicate this
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is part of a is equal to the number of
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turns in the coil times. The magnetic field time
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is the area multiplied by Omega times. The sign
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omega times time. Well, since the sign of
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a value gives you a number between zero and one
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, this is maximum when sign of omega T is
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one. So we can say Max. Yeah,
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sign omega T equal to one. Therefore, we
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can say e max is equal to the number of
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turns multiplied by the magnetic field well supplied by the
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area well supplied by omega plugging those values and its
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expression, we find that this is equal to 7.5
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times 10 to the third volts or 7.5 kilovolts since
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10 to the third is equal to the kill of
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all weaken box set in as a solution to our
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question for part A. Now for Part B,
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it says When the maximum induced voltage occurs, What
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is the orientation of the coil with respect to the
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magnetic field? Well, the orientation of the coil
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with respect to the magnetic field is discussing that sign
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of omega T term. But again, that's maximum
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and sign of omega. T is equal toe,
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um, one. So, since uh, that's
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true, this has to be at an angle of
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fada, since if we're considering Omega T to be
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fada of 90 degrees or the opposite 270 degrees,
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since that is when the sign of that value is
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equal to one. So this is when the normal
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vector of the coil is parallel to the D field
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with a magnetic field. So let's go back to
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that page so we can say down here when normal
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factor of coil is parallel to the magnetic field or
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the D field. And this is all our solution
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to part B, so we can go ahead and
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box all of this in