WEBVTT
1
00:00:00.940 --> 00:00:02.890 A:middle L:90%
So we want to show that for motion in a
2
00:00:02.890 --> 00:00:07.410 A:middle L:90%
straight line with constant acceleration, initial velocity and initial
3
00:00:07.410 --> 00:00:12.169 A:middle L:90%
displacement Vienna and S not, respectively, that we
4
00:00:12.169 --> 00:00:16.239 A:middle L:90%
have our displacement after time. T. Is S
5
00:00:16.239 --> 00:00:18.820 A:middle L:90%
. Equals one half a T squared because Vienna T
6
00:00:18.820 --> 00:00:22.250 A:middle L:90%
plus asthma. So our constant acceleration A. Which
7
00:00:22.250 --> 00:00:24.829 A:middle L:90%
means R a F. P function, it's just
8
00:00:24.829 --> 00:00:28.809 A:middle L:90%
constant acceleration act. And that tells us that our
9
00:00:28.809 --> 00:00:35.049 A:middle L:90%
velocity function is equal to 80 because aid constant plus
10
00:00:35.439 --> 00:00:42.299 A:middle L:90%
Vienna, our velocity constant. Um in this case
11
00:00:42.310 --> 00:00:44.700 A:middle L:90%
uh this would be plus C. But because we
12
00:00:44.700 --> 00:00:47.679 A:middle L:90%
know that Vienna is the initial velocity will put that
13
00:00:47.679 --> 00:00:50.850 A:middle L:90%
there. And we want to find our ask our
14
00:00:50.850 --> 00:00:54.780 A:middle L:90%
position function that's going to be a T squared over
15
00:00:54.780 --> 00:01:00.710 A:middle L:90%
two plus B, not T. Empty plus our
16
00:01:00.710 --> 00:01:03.769 A:middle L:90%
initial position which is S not. So therefore we
17
00:01:03.769 --> 00:01:06.959 A:middle L:90%
have proven what we wish to prove.