WEBVTT
1
00:00:00.540 --> 00:00:03.140 A:middle L:90%
for the given problem, we want to evaluate to
2
00:00:03.140 --> 00:00:07.339 A:middle L:90%
some of the factors knowing that vector A is going
3
00:00:07.339 --> 00:00:14.730 A:middle L:90%
to be 8 1-4 And the B vector is
4
00:00:14.730 --> 00:00:22.359 A:middle L:90%
going to be 5-2, 1 with some of
5
00:00:22.359 --> 00:00:25.350 A:middle L:90%
these vectors. If we do A plus B,
6
00:00:26.140 --> 00:00:30.739 A:middle L:90%
okay, is going to be the component added together
7
00:00:30.739 --> 00:00:33.789 A:middle L:90%
. So eight plus 5 13, 1 minus two
8
00:00:33.789 --> 00:00:37.579 A:middle L:90%
, negative one and negative four plus one negative three
9
00:00:38.640 --> 00:00:40.500 A:middle L:90%
. Then we want to find the magnitude of a
10
00:00:40.500 --> 00:00:42.450 A:middle L:90%
. So magnitude of A is going to be the
11
00:00:42.450 --> 00:00:48.329 A:middle L:90%
square root of eight squared, which is 64 Plus
12
00:00:48.329 --> 00:00:52.450 A:middle L:90%
one Squared, which is one Um plus a negative
13
00:00:52.450 --> 00:00:55.420 A:middle L:90%
4th grade, which is 16. That takes us
14
00:00:55.420 --> 00:01:00.810 A:middle L:90%
to 81 squared of 81 we know is nine.
15
00:01:00.820 --> 00:01:03.359 A:middle L:90%
So that's the magnitude and this is the final answer
16
--> A:middle L:90%
.