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1
00:00:00.780 --> 00:00:04.840 A:middle L:90%
we know substituting X and Z 12 or 12 plus
2
00:00:04.839 --> 00:00:09.410 A:middle L:90%
24 gives us 12 over 36 12 and 36 or
3
00:00:09.410 --> 00:00:11.519 A:middle L:90%
both. Divisible by 12 divided top and bottom by
4
00:00:11.519 --> 00:00:12.899 A:middle L:90%
12 we get one over three.