WEBVTT
1
00:00:01.439 --> 00:00:06.299 A:middle L:90%
So here we want to start by factoring now this
2
00:00:06.299 --> 00:00:15.359 A:middle L:90%
denominator we have. So it's only right that 1/3
3
00:00:15.839 --> 00:00:18.750 A:middle L:90%
. So we have a numerator t squared minus one
4
00:00:19.940 --> 00:00:23.260 A:middle L:90%
. So we can write T the 4th-1 as
5
00:00:25.039 --> 00:00:31.100 A:middle L:90%
so t squared last one multiplied by t squared plus
6
00:00:31.100 --> 00:00:37.460 A:middle L:90%
one. So now we can cancel out the numerator
7
00:00:37.939 --> 00:00:45.590 A:middle L:90%
in his first term of the dominator. See we'll
8
00:00:45.590 --> 00:00:52.399 A:middle L:90%
get one over T squared plus one. And now
9
00:00:52.399 --> 00:00:54.560 A:middle L:90%
we can refer to the Table of indefinite Girls.
10
00:00:55.240 --> 00:01:00.250 A:middle L:90%
Which will tell us that this integral will be inverse
11
00:01:00.250 --> 00:01:11.659 A:middle L:90%
tangent or arc Itandje in of t Upper bound 1/3
12
00:01:11.340 --> 00:01:17.359 A:middle L:90%
. Lower bound of zero. So let's evaluate this
13
00:01:19.840 --> 00:01:26.900 A:middle L:90%
. Our tangents foreign over route three minus or a
14
00:01:26.900 --> 00:01:37.069 A:middle L:90%
tangent of zero. Arc tangent 1/3 Will be Pi
15
00:01:37.129 --> 00:01:41.349 A:middle L:90%
over six. Whatever route through. Excuse me,
16
00:01:41.739 --> 00:01:45.819 A:middle L:90%
Might start changing of zero this 0. So our
17
00:01:45.819 --> 00:01:48.629 A:middle L:90%
answer is Pi over six.