WEBVTT
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Newton's second law tells us that the net force it's
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not, is equal to the match off the car
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. Times declaration. We know the math of the
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car is equals. True, one, 580 kilo
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grams. It isn't with a play about acceleration.
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Now we have to calculate what is the relation of
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this car? How can we do that? Well
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, we have the variation in the velocity and we
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have the displacement that happen why August velocity was creating
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. But we don't know what is the time interval
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in between these three events. So when you don't
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have time, we used to return his equation,
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which in the following the final Velocity Square is equal
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to the initial velocity squared quest to times declaration,
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times displacement. So in this question, the final
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velocity is close to zero. The initial velocity vehicles
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to 15. Um, we have two times declaration
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that we want to calculate times the displacement off 50
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meters. Then we go minus two times declaration times
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50 whose egos to 15 square miners. Because we've
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sent this turn to the other side. Then we
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get it that the acceleration is because two minors it's
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been squared divided by two times 50. We just
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sent both the truth and the 50 to another side
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. The hiding. Then acceleration is equal to minus
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if squared, divided by 100. And this is
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equally true. Minus 225 divided by 100 which is
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minors to going 25 meters per second. Squared the
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observations negative because the velocity is being reduced. Then
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we can plug in the velocity that we have just
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calculated. Even you turn second law equation to get
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the following that horse that's next is he goes to
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150 times minus two point point five. This gives
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us a net force approximate minus 3560 new toes.