WEBVTT
1
00:00:00.530 --> 00:00:03.950 A:middle L:90%
in this exercise. We have an atom at the
2
00:00:04.339 --> 00:00:07.540 A:middle L:90%
fourth energy level and equals four. And in question
3
00:00:07.549 --> 00:00:11.060 A:middle L:90%
A. We want to know how many different values
4
00:00:11.070 --> 00:00:14.279 A:middle L:90%
of El that is. The orbital frontal number are
5
00:00:14.279 --> 00:00:18.760 A:middle L:90%
possible. So remember that for a given end given
6
00:00:18.760 --> 00:00:23.079 A:middle L:90%
energy level when he allowed, uh, L Z
7
00:00:23.079 --> 00:00:27.710 A:middle L:90%
allowed orbital frontal numbers are ranged from zero to n
8
00:00:27.710 --> 00:00:31.690 A:middle L:90%
minus one between. In this case, we have
9
00:00:31.699 --> 00:00:38.350 A:middle L:90%
the possible else 012 and three. So in total
10
00:00:38.840 --> 00:00:50.469 A:middle L:90%
, there are four allowed else. Okay, And
11
00:00:50.469 --> 00:00:54.649 A:middle L:90%
for a question, be have to find Khomeini allowed
12
00:00:55.240 --> 00:00:59.350 A:middle L:90%
magnetic quantum numbers. There are. Okay, so
13
00:00:59.350 --> 00:01:03.040 A:middle L:90%
remember that for a given l the allowed magnetic quantum
14
00:01:03.040 --> 00:01:10.719 A:middle L:90%
numbers range from minus l to l. So the
15
00:01:10.719 --> 00:01:15.250 A:middle L:90%
largest l possible as we saw in question A is
16
00:01:15.260 --> 00:01:19.349 A:middle L:90%
l equals three. Okay. And in that case
17
00:01:19.790 --> 00:01:23.670 A:middle L:90%
, M l can be minus three minus two minus
18
00:01:23.670 --> 00:01:29.519 A:middle L:90%
one zero one, two and three. Notice that
19
00:01:29.530 --> 00:01:33.129 A:middle L:90%
in total there are seven. Okay. And this
20
00:01:33.129 --> 00:01:42.879 A:middle L:90%
is this is the the number of allowed magnetic quantum
21
00:01:42.879 --> 00:01:46.150 A:middle L:90%
numbers and else Okay, total there are seven.
22
00:01:47.439 --> 00:01:48.950 A:middle L:90%
And this concludes the exercise