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all right. So here we have a rough sketch
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of the graph of F, and it's 1 to
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1 because every X value has only one y value
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and every y value has only one X value.
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And graphically, we can say it passes the horizontal
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line test as well as a vertical line test.
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Okay, now we went to find the domain and
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range of F inverse. So first of all,
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let's find the domain and range of F. So
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the domain of F the X values that goes through
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our negative 3 to 3 on the range of death
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, the Y values that goes through our negative 123
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So the domain of F inverse will be the range
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of F, and the range of FM burst will
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be the domain of F. So we're going to
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switch these and the domain of F inverse will be
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from negative 123 and the range will be from negative
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3 to 3. When you have an inverse outputs
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become inputs, inputs become outputs. All right.
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Now let's find the value of f inverse of to
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so effin versus to let's say it equals X,
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then that means that f of X equals two,
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the output of X inverse will be the inverse will
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be the input of F inputs and outputs are switched
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. So what? X value appears to have a
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Y value of two. Looking at the graph,
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it looks like X equals zero has a Y value
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of two. So f inverse of two is zero
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. And finally, let's estimate the value of F
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inverse of zero. So similarly, let's just say
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that it's X, so that means that f of
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X equals zero. So we're estimating the value of
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the point where there's a wide coordinate of zero on
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the graph. Now you really should look at the
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graph in the book, not my graph, because
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mine is just a rough sketch. And if you
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look at the graph in the book, you see
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that it passes through a height of zero at about
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negative 1.5 negative 1.6 somewhere in there, so f
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inverse of zero is approximately negative. 1.6