WEBVTT
1
00:00:00.080 --> 00:00:05.589 A:middle L:90%
less determined whether the Siri's convergence or diverges now,
2
00:00:06.639 --> 00:00:11.960 A:middle L:90%
since three into the fourth plus one, is bigger
3
00:00:11.960 --> 00:00:19.339 A:middle L:90%
than three into the fourth. This means at the
4
00:00:19.339 --> 00:00:27.500 A:middle L:90%
Q brew is also larger. But this means that
5
00:00:27.500 --> 00:00:32.649 A:middle L:90%
if I flip both sides and after flipped inequality as
6
00:00:32.649 --> 00:00:45.049 A:middle L:90%
well, therefore over here, I could actually just
7
00:00:45.049 --> 00:00:49.579 A:middle L:90%
use less than I guess, because I am going
8
00:00:49.579 --> 00:00:51.950 A:middle L:90%
to infinity. I should put equals just in case
9
00:00:51.950 --> 00:00:57.369 A:middle L:90%
they're they're both infinity, So one over Q Brew
10
00:00:57.369 --> 00:01:00.820 A:middle L:90%
of three. Answer the fourth. Now let's go
11
00:01:00.820 --> 00:01:15.040 A:middle L:90%
in and simplify this. So that's our P value
12
00:01:15.049 --> 00:01:17.019 A:middle L:90%
. We see that we have a P series here
13
00:01:17.969 --> 00:01:22.170 A:middle L:90%
and equals one to Infinity won over the humor of
14
00:01:22.170 --> 00:01:26.140 A:middle L:90%
three times and so the for over three. So
15
00:01:26.140 --> 00:01:37.769 A:middle L:90%
this convergence by the Peters with P equals for over
16
00:01:37.769 --> 00:01:42.180 A:middle L:90%
three, and that's bigger than one. So by
17
00:01:42.180 --> 00:02:05.819 A:middle L:90%
the comparison test, our Siri's also emerges, and
18
00:02:05.819 --> 00:02:06.709 A:middle L:90%
that's your final answer.