WEBVTT
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to solve this question, we can apply Newton's second
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law on the vertical access. I would choose that
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everything that is pointing up its positive on everything that
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is pointing down as negative as a consequence. Then
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Newton Cycle Low tells us that the net force that
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acts on the fish is it close to the mass
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off the fish times its acceleration. If the fish
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is being pulled up with a constant velocity, its
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acceleration is because 20 then the net force that acts
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on the fish is of course, zero. But
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the net force is composed by true forces attention force
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that is pointing up miners the weight force that is
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pointing down. Then the tension force should be you
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close to the weight off the fish. But the
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maximum tension that the line can sustain is 45 Newtons
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. Therefore, for the maximum tension we have 45
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Newtons equals to the weight off the heaviest fish that
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can be fish it under this conditions. On the
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next item, we have an acceleration. So the
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net force that acts on the fish is it goes
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to the mass off the fish times its acceleration,
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which is equals to two meters per second squared in
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the second situation. Now the net force is again
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composed by two forces. That tension forced miners the
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weight force and these is of course to the mass
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times acceleration. Therefore, by solving this equation for
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the weight, we get the following the tension minus
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two times the mass off the fish. Is it
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close to the weight off the heaviest fish that can
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be fissured Under these conditions, the tension is equals
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to 45 new terms on extremo situation. So this
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miners two times the mass off the heaviest fish should
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be equal to the weight off that fish. But
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the weight is given by the mass off the heaviest
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fish times. The acceleration of gravity, which is
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approximately 9.8 meters per second squared then is equals true
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am times 9.8. So now we can solve this
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equation for the mass and then calculate what is the
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weight? Then we got the following 45 is he
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goes to 9.8 times the mass plus true plans.
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The mass 45 then is equals to 11.8 times the
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mass. So the mass off the heaviest fish is
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45 divided by 11.8, then the weight off The
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heaviest speech is the coast to 45 divided by 11.8
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times 9.8 meters per second squared on these results in
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approximately 37 Newtons.