WEBVTT
1
00:00:01.040 --> 00:00:03.960 A:middle L:90%
this question shows is a table of prices over the
2
00:00:03.960 --> 00:00:07.139 A:middle L:90%
several years for bushels of wheat. It asks us
3
00:00:07.139 --> 00:00:10.259 A:middle L:90%
to find the mean and the median the price is
4
00:00:10.259 --> 00:00:19.050 A:middle L:90%
that it gives in order. Are 2.62 2.78 3.56
5
00:00:19.600 --> 00:00:31.649 A:middle L:90%
3.40 3.40 3.42 4.26 Sturgeon of the line. 6.48
6
00:00:33.539 --> 00:00:41.799 A:middle L:90%
6.78 and 4.7. We knew that the mean our
7
00:00:41.810 --> 00:00:45.960 A:middle L:90%
export is just the sum of all the exes divided
8
00:00:45.960 --> 00:00:48.520 A:middle L:90%
by n where n is the number of data points
9
00:00:48.520 --> 00:00:51.189 A:middle L:90%
that we have here. We know N is 10
10
00:00:51.939 --> 00:00:53.640 A:middle L:90%
. And if we add up, all of our
11
00:00:53.640 --> 00:00:56.020 A:middle L:90%
data and a calculator will get this. Some of
12
00:00:56.030 --> 00:01:02.320 A:middle L:90%
the excess is we go to 41.57 So pretty quickly
13
00:01:02.329 --> 00:01:04.989 A:middle L:90%
we can figure out that explore is 41.57 out of
14
00:01:06.000 --> 00:01:11.670 A:middle L:90%
10 or just 4.157 Next, we need to find
15
00:01:11.670 --> 00:01:14.769 A:middle L:90%
the median. To do that. I want to
16
00:01:14.769 --> 00:01:17.349 A:middle L:90%
put this list of numbers that we have in order
17
00:01:18.540 --> 00:01:19.920 A:middle L:90%
. That is, I'm going to go from lowest
18
00:01:19.920 --> 00:01:23.579 A:middle L:90%
to highest strolled down and rewrite it. First we
19
00:01:23.579 --> 00:01:34.060 A:middle L:90%
have 2.62 then 2.78 men 3.4. Another 3.4 a
20
00:01:34.060 --> 00:01:51.549 A:middle L:90%
3.42 a 3.56 a 4.26 4.87 6.48 and a 6.78
21
00:01:52.739 --> 00:01:53.609 A:middle L:90%
Now, we know we haven't even number here.
22
00:01:53.609 --> 00:01:57.709 A:middle L:90%
We get any cost. 10. So to find
23
00:01:57.709 --> 00:02:02.230 A:middle L:90%
the median, we're gonna find, um, point
24
00:02:02.230 --> 00:02:07.430 A:middle L:90%
the data in place five and place six and average
25
00:02:07.430 --> 00:02:10.120 A:middle L:90%
them. So I counted out 1234 Here's five and
26
00:02:10.120 --> 00:02:13.270 A:middle L:90%
six. So our median is going to be the
27
00:02:13.270 --> 00:02:15.860 A:middle L:90%
average of these two. When we add these two
28
00:02:15.860 --> 00:02:16.629 A:middle L:90%
together and divide by two, we get that are
29
00:02:16.629 --> 00:02:23.759 A:middle L:90%
median is equal to 3.4 nine, and that's your
30
00:02:23.759 --> 00:02:23.439 A:middle L:90%
final answer.