WEBVTT
1
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in orderto find the volume we know we're integrating along
2
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the access parallel to the axis of rotation. We
3
00:00:06.190 --> 00:00:09.080 A:middle L:90%
know the axis of rotation is y equals one There
4
00:00:09.080 --> 00:00:11.910 A:middle L:90%
, for the outer radius is simply one. The
5
00:00:11.910 --> 00:00:15.240 A:middle L:90%
distance from Y equals zero to the oxygen rotation,
6
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which we establish is Michael's one, and the in
7
00:00:18.289 --> 00:00:21.199 A:middle L:90%
a radius is one minus acts again for the same
8
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reasons. Therefore, our volume This pot times the
9
00:00:25.050 --> 00:00:29.800 A:middle L:90%
integral from 01 of one squared, minus one minus
10
00:00:29.809 --> 00:00:39.259 A:middle L:90%
acts remembered outer minus inner foil and cause bind like
11
00:00:39.270 --> 00:00:47.159 A:middle L:90%
terms. Now we can integrate. Use the power
12
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rule, increase the expert by one divide by the
13
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new exponents. Now we can plug in. We
14
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end up with two pi over three.