WEBVTT
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and this problem we want to find the limit is
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ex Purchase two off. The constant function f of
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X equals negative one. So it can't have that
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re written right here. So our post answer is
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that the limits equal to make one. So if
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you kind of graph that function, you'll see that
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you have a horizontal line located at negative one.
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So actually the limit is X approaches. Any real
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number for this function will be negative one. So
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that's kind of thie intuition behind thiss proposed answer here
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. We want to show this using an absolute delta
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proof that is, we want to show that for
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every Absalon greater than zero, there is a delta
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greater than zero such that negative one minus negative one
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is less than epsilon. Whenever zero is less than
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the absolute value of X minus two is less than
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don't. So, first, we should note that
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if we have no the absolute value of negative one
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minus negative one, it's less than absolutely then if
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we simplify that we have that zero in absolute value
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is less than Epsilon. And we can write that
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because the up survive. Sarah was only Cero.
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So that leaves Ciro is less then. Absalon.
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So this may look a little strange, but we'll
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see that our problems became a lot more simple here
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. Because remember, we have this found up here
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, two on the absolute value of X minus two
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. We don't know that that's between zero and Delta
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. So that right here and say this definitely implies
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that Ciro is less than daughter if we kind of
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take out this middle part. So if we let
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Absalon Keyhole to doubt her Yeah, then we have
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thie. Absolute value of negative one, Linus.
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Negative one, which is equal too. So which
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is certainly us, then Delta, which is he
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called to Absalon. And we're done. Yeah.