WEBVTT
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kept. So four problem. Three. All right
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, we have derivative off a function which is X
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minus one squared times X plus two. So similarly
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, uh, 1st 1st part, we need to
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find the, uh, critical points. So excuse
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me. That is to let this derivative to be
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equal to zero. Now, the solution will be
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X. What next? A sequel to one and
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when next is equal to negative too. Okay.
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No, To find the opening a rose for increasing
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and decreasing, we need to let the due to
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to be pause, do first. Now to solve
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this, um, to solve his inequality. The
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first thing we need to observe is dead X minus
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one squared will always be the negative. So that
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means we don't allow acts to be one. And
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at the same time, you should add in.
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And so, at the same time, we need
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to make experts to haunted. So that is,
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that gives the interval, which is from, uh
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let's see. Yeah, pushes for elective too.
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21 Union one to infinity. And on this interval
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, the function will increase. And other than that
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, we will have the interval for decreasing, which
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is from negative. Infinity to elective too. Okay
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, now, Parsi. Now what are we going
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to do is to find a local maximum local animals
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. So it's quite simple. We just need to
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find We just need to check the locally streak.
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Lovely stream points. But the thing to notice instead
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, one is not. It's not a loco extreme
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. The reason is because we just exclude one from
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our increasing interval. And that means when x x
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equal to one, nothing will happen because he will
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keep increasing. So if one is not a local
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extreme, but have connected to will be a no
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Cole. This should be a local mutual okay and
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correspondent in there. There is no local man in
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Mexico.