WEBVTT
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to complicate the value off the tension. For the
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first item, we can use Newton's second law on
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these block. So for the first item we have
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that the net force acting on these direction, which
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are you call the Y direction is equal to the
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mass off block number chew. These is a block
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number choo times Next iteration off block number. Truth
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, then the net force that acts on this block
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is composed by true three forces. So really,
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it's two times the tension minus Don't wait number true
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and this is the mass number two times acceleration number
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. Truth. I noticed that Block number two we'll
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move downwards. Therefore its acceleration is negative. So
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let us include these information in this equation. So
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here we have minus and two times a truth where
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the minus sign is because this block we'll move down
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Onley. One equation is insufficient because we have to
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discover what is attention on what is the acceleration.
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So we need more equations. Another equation that we
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can use his Newton's second law for these block on
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the horizontal direction which have called the X direction.
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So for the other book on the X direction we
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have that the net force acting. No need in
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that direction is it goes to the mass off block
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number one times acceleration off block number one A one
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them. The net force that acts on these access
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is equal to the tension force. So the tension
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is because the acceleration off block number one times its
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mass. But it's still not sufficient because we have
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123 announced and only two equations for them. What
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can we do? We can use the hint.
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The hint tells us that the larger mass moves twice
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a Sfar as this mother Mass. So it's telling
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us that the acceleration off the larger mass, which
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is mass number one, is equals to two times
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the acceleration off this mother must, which is a
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truth. Now that we have three equations and three
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announce, we are able to solve the system before
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serving it. Let me organize my board to solve
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this system of equations. We begin by using the
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result from Equation three into equation truth. So using
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the question tree in Equation two, we get the
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following. The tension is because, too, and
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one times true times, a true and this gives
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us letting say equation 2.1, then by using equation
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2.1 into equation number one, we get true times
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M one times true times A true miners wait number
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true is equals to minors. I m too times
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a truth. Then we can solve this equation for
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h you in order to get the acceleration number two
51
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. For that, we sent this term to the
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other side on this term to the other side to
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get work times. I am one times a true
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plus and true times eight you Is it close to
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the weight number two? Then we can factored acceleration
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over truth and write it as four times m one
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plus and chew is equals to delete number. True
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, then the acceleration Number two is equal to the
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weight number two which is m two times g,
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divided by four times and one plus m two bloody
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And the violence that the problem gave us We get
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three times nine point Kate divided by four times 10
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plus street and these results in an acceleration off approximately
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zero 0.6 83 meters per second squared then using this
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value for a tree. We can go back to
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Equation 2.1 and company to detention. These results in
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the following detention is it close to M one which
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is 10 times truth times a truth which is 0.6
69
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83 These results in attention off approximately starting 0.7 mutants
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. Then for the next item, we have to
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calculate what is a one the acceleration off the larger
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block on for a one. We just have to
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use this value for eight years into equation number three
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. By doing that, we get a one is
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equals to two times 0.683 and these results in approximately
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one point 37 meters per second. Squared on these
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is the acceleration off the larger book.