WEBVTT
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we begin this question by can't leading the acceleration of
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gravity on the surface off these other planet. So
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remember that the surface gravity off any planet is it
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goes to Newton's constant times. The mass off the
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planet divided by the radios, squared off this planet
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. So for planet earth, we have a gravitational
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acceleration that is given by G m. E,
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divided by the radios off the earth squared for the
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other planet we have the following It is it goes
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to g times the mass off the other planet divided
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by the radios off this other planet squared. But
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the mass off the other planet is because to three
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times the mass off the earth and at the same
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time the radios off this other planet is it goes
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to two times the radios off the earth. So
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we have two times r e squared here and this
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gives us g times m e divided by r e
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squared times three divided by four. And this is
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nothing else than the surface gravity off the Earth Time
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Street, divided by four. Therefore, exploration off
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the gravity on the surface off this other planet is
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equals to 3/4 Deceleration off gravity on the surface off
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your now we proceed to couple eating. What is
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the weight off? That's place traveller on the surface
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off these other planet. Remember that the weight force
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is given by the mass times acceleration off gravity The
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reform The mass off this place traveller on the earth
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is equals to the mass off the space traveler which
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is a known times next relation off the gravity on
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the surface of the earth. At the same time
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, the weight off the space traveler on the surface
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off this other planet is equals to the mass off
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the space traveler times acceleration off gravity on the surface
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off this other planet. But as we have calculated
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, the acceleration of gravity on the surface off the
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other planet is equals to 3/4 explanation of gravity on
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the surface of the earth. So these is equal
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to the mass off the astronaut times 3/4 crimes the
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gravity on the surface off the earth and this is
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equals 234 times the mass times the gravity from the
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earth. And this is nothing else than the weight
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off the space traveler on the Earth before the weight
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off the space traveler on these other planet is,
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he goes to 3/4 times the weight off this space
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traveler on the Earth, which is equals to 540
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new terms. So we have 3/4 off, 540
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which is equals to 405 new terms. So the
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weight off the space travel on the surface off these
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other planet is equals to 405 new towns.