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Okay, So for prom night, um, if
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the ribs were given ISS one minus four over X
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squared where asked Ex cannot be zero. So the
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first thing we need to do is to find the
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critical points that is to let the derivative to be
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equal to zero on DDE This case, we can
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find a solution, which is positive or negative too
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. Okay, now for party, let's first let
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the derivative to be positive now, by solving this
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inequality we can find. So the first thing we
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can do is to won't apply X squared on both
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sides. So that's X squared minus four, bigger
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than zero. So that means X squared is strictly
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bigger dead for hens. Our acts should be bigger
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than two or X. Be smaller than next to
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. So that means, um, like to be
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ability to thank you too. Union Two, two
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You been t on this interval function will be increasing
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and I think to to to his function will be
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decreasing. Oh, I'm sorry. Um, remember
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that we don't allow X to be zero, so
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we have to act. I have to exclude zero
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from this interval, so that means our our interval
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for decreasing will be from negative 2 to 0.
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Union 02 hostile to. Okay, now for Parsi
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. Now. See you. We need Thio.
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We need to find a local Mexico. My local
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minimum. Well, in this case, we observed
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these two intervals. Then we can find, uh
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, connected to we'll be the local maximum and half
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of two will be the local minimum.