WEBVTT
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the first thing we should do here is such a
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cz factor that the not leader as much as we
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can. So here will get X squared minus four
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x squared plus four. And then we should check
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to see if he's fatter. So if we look
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at the first one here, this is just X
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plus two X minus two about the second one.
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Well, this one factor. So you look at
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the discriminatory here, B squared minus four a.
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C. It's a negative number here for this problem
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. For this x squared plus four. So that
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means it does not factor. So have to write
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it like that. And then we could go straight
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to the partial fraction so constant for the first two
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and then because we have irreducible contract IQ on the
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bottom and green, we have to put a linear
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up top. So we have CX plus de.
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So here, let me write this. We have
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to find a B C ity. Of course.
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So is And I got him on over thirty two
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. Be positive on over thirty two, and then
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we have that c zero and dia's minus one over
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eight, So I just pulled off the minus there
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. And then we have X square plus four.
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Now, the first two hundred girls, those air
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easier. And then we have one over thirty two
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l. A cops. Thirty two. They're not
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me. That's sloppy There. And then here we
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have X minus two. And then for this last
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inner girl here a little more difficult. In the
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first two, you could do a train from here
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, but sixty toothy data. And so when we
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integrate, this will have the one over eight with
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the minus from disturb right here and then after interbreeding
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. That's ten inverse of X over to and then
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divide by two again, all coming from the tricks
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up over here. Let me just go to the
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next page and write that out. So combining the
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log rhythms. So here, just combining log using
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the law of properties and then combining the the two
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that sixteen. And that's your final answer