WEBVTT
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So for first problem will be answering a couple of
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questions regarding the reaction, Um, as seen about
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. And so for the first part, identify the
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type of reaction we can see that we have one
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reactant, um, in a chemical reaction, turning
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into two products. And so this is a de
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called position reaction because it follows the format of see
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breaking down to a plus speak. So for the
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second part, we will determine the Mueller Mass of
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each molecule. And to do that, we can
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use the periodic table to figure out the mass of
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each atom and then accordingly determine the molar mass.
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So for a nitric acid, this would be 1.8
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from the region, um, added to 14.1 from
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the nitrogen and three oxygen atoms. And so this
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would be 63 point 02 g Permal. And now
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we're going to do the same thing for the Armel
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you'll. So we have nitric oxide, which is
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just 14.1 from the nitrogen plus 16.0 from the oxygen
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, which will give us a more mass of 30.1
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grams, Permal and lastly for oxygen, this would
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be two times the atomic mass of hydrogen plus oxygen
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, which will deal a similar mass of 18.2 grams
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Permal. And so for the final part of the
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problem, we need to determine the percentage composition of
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the reactive. So there is only one reacted,
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which is nitric acid. And so to do this
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, we need to use the Mueller math of nitric
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acid, Um, and the appropriate, um,
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total mass of each item to obtain the percentage composition
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. So in nitric acid, there is only one
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atom of hydrogen. And so that would mean that
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we would only have 1.8 numerator and we will divide
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this by the Mueller Mass of the molecule, which
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will give us 0.1 589 And when we convert that
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to percentage, that is one point 589 present.
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And now we're going to do the same thing for
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nitrogen. And so there is only one out of
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dimension and so this value would be 14.0 went and
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then you're going to divide this by the more mass
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to obtain 0.22 to 3. And when you convert
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that to a percent, this would be 22.23%.
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And lastly, for oxygen, we have three atoms
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of oxygen. So then we need to multiply three
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by the mass of one oxygen atom, and then
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divide this by the molar mass of the molecule just
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again. 63.2 And what we end up with is
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the dust mall, 0.7618 and in percentage. This
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would be 76.18%. And so this would be the
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percent composition of the reactive. And whenever you determine
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the percent composition, you always want to make sure
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that the percentage is that you get will add to
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100 s. So we can quickly do that on
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the side just to make sure that the math is
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correct. And so if we write this out and
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these numbers together, we actually end up with 99.999
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And if you run this, this should be 100
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. And so after a double checking our answer,
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um, this shows us that we have a deed
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found the correct percent composition of the metric acid,
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which is the reactant in this reaction