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So picking we have the second derivative of X.
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And it's equal to four plus six X plus 24
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X. Screwed. So when we evaluate this,
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when you take F prime of X using the anti
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derivative we get four X plus um free X squared
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plus. He acts cute Classy. But we know
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that F of zero is three. So what we're
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gonna end up getting is Or f of f prime
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of one is 10. So we're going to end
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up getting to as R. C value. Then
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we have F of X. Which is going to
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give us um to have squared plus X cubed Class
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two X to the 4th plus two X plus another
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constant value. But we know that F of zero
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is three. That means as constant as three.
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Therefore our final anti derivative is two X squared plus
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X cubed plus two X. To the fourth plus
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two X plus three. Final answer.