WEBVTT
1
00:00:04.339 --> 00:00:07.410 A:middle L:90%
Hi. We've got a question here asking the probability
2
00:00:07.410 --> 00:00:09.849 A:middle L:90%
that a hit was made by Ty Cobb given that
3
00:00:09.849 --> 00:00:12.519 A:middle L:90%
the hit was a homerun and we have a table
4
00:00:12.519 --> 00:00:15.539 A:middle L:90%
of information right above to help us with that answer
5
00:00:15.919 --> 00:00:19.809 A:middle L:90%
. Remember that the probability of any than A given
6
00:00:19.809 --> 00:00:24.949 A:middle L:90%
B is equal to the probability of A and B
7
00:00:26.339 --> 00:00:32.450 A:middle L:90%
over the probability of B. So in this case
8
00:00:32.509 --> 00:00:38.649 A:middle L:90%
, we're trying to find the probability of Ty Cobb
9
00:00:39.340 --> 00:00:46.200 A:middle L:90%
and ah, home run over the probability of home
10
00:00:46.200 --> 00:00:51.049 A:middle L:90%
runs. So to find our answer, we're gonna
11
00:00:51.049 --> 00:00:55.060 A:middle L:90%
find the Ty Cobb bro and find the home run
12
00:00:55.060 --> 00:01:00.359 A:middle L:90%
column. And where they meet is this 114 and
13
00:01:00.369 --> 00:01:04.290 A:middle L:90%
then the home run column itself, which would be
14
00:01:04.290 --> 00:01:07.769 A:middle L:90%
our total for home runs for the bottom. We
15
00:01:07.769 --> 00:01:10.450 A:middle L:90%
go to the bottom of that that 17 20.
16
00:01:10.939 --> 00:01:12.209 A:middle L:90%
And if you look at her choices since this one
17
00:01:12.209 --> 00:01:15.489 A:middle L:90%
doesn't actually have it divided out, its choice B
18
00:01:15.489 --> 00:01:21.250 A:middle L:90%
1 14 over 17 20. Thank you.