WEBVTT
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in this problem who want to show that the limit
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is X approaches. Pi of the function f of
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X is equal to pi. Now we know that
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the limit is pie because if we look at the
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graph of F which is depicted here on the left
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, we can see that after Lex approaches pi from
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the left hand side of X equals pi Analects approaches
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pi as well on the right side of X equals
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pi. So from the graph, we can conclude
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that the limit is part. Now we want to
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prove pious the limit by using the Epsilon Delta definition
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off limits. That is, we want to show
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that for every excellent greater than zero, there's a
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delta greater than zero such that X minus pi.
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Absolute Valium is less than epsilon whenever the absolute value
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of X minus pi is in between zero and delta
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. So here we let Delta Echo Absalon. By
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doing that, we see that the absolute value of
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X minus pine is then less than delta which is
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equal to Absalon. So consequently the absolute value of
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X minus pi is less than excellent and we're done
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No