WEBVTT
1
00:00:00.510 --> 00:00:04.750 A:middle L:90%
so recall that with a constant speed, distance is
2
00:00:04.750 --> 00:00:07.690 A:middle L:90%
going to be able to velocity times time. So
3
00:00:07.690 --> 00:00:11.750 A:middle L:90%
if our distance is 50 miles and our velocities X
4
00:00:12.390 --> 00:00:17.230 A:middle L:90%
and then our time is why then he saw for
5
00:00:17.230 --> 00:00:20.260 A:middle L:90%
why why is going to be 50 over x?