WEBVTT
1
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there is someone You right here. So we have
2
00:00:01.860 --> 00:00:08.109 A:middle L:90%
G FX is equal to x square comes one minus
3
00:00:08.119 --> 00:00:14.640 A:middle L:90%
two X which is equal to X square minus to
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00:00:14.650 --> 00:00:22.199 A:middle L:90%
execute on. We can write this. It was
5
00:00:22.199 --> 00:00:26.859 A:middle L:90%
a derivative of D over DX. In terms of
6
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X, x square minus to execute, we're gonna
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00:00:34.869 --> 00:00:37.929 A:middle L:90%
apply the difference rule. So what we're gonna do
8
00:00:37.929 --> 00:00:45.280 A:middle L:90%
is do you over D X looks square minus the
9
00:00:45.280 --> 00:00:52.759 A:middle L:90%
over DX to execute, and this becomes equal to
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00:00:52.770 --> 00:00:56.689 A:middle L:90%
two X minus six x squared.