WEBVTT
1
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Okay, so we're gonna create a table, fine
2
00:00:05.639 --> 00:00:08.250 A:middle L:90%
its limit knowing. So it's let X equal to
3
00:00:08.740 --> 00:00:14.570 A:middle L:90%
1.9. We get 1.9 over 1.9 plus one to
4
00:00:14.570 --> 00:00:21.960 A:middle L:90%
over three over 1.9 minutes to This is approximately 0.114943
5
00:00:22.440 --> 00:00:24.879 A:middle L:90%
Okay, so we could do the same for 1.99
6
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I won't show the works if we're just putting that
7
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into our function rally we get. This is approximately
8
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0.111 were a tree. The next you could feel
9
00:00:34.250 --> 00:00:41.380 A:middle L:90%
1.999 you get. This is approximately 0.1111148 Now,
10
00:00:41.380 --> 00:00:44.270 A:middle L:90%
when X is equal to we get undefined. But
11
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you're subjecting two by two and are enumerated are denominated
12
00:00:48.280 --> 00:00:53.140 A:middle L:90%
. So we're get division by now. When X
13
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is equal to if you 0.1, we get our
14
00:00:57.350 --> 00:01:03.649 A:middle L:90%
value. Why is approximately quite 111? Go 74
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00:01:03.239 --> 00:01:08.670 A:middle L:90%
Okay, so we see there are limits as experts
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to our function. Coaches approximately won over nine,
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which is equal to 2.1111 Let me check that