WEBVTT
1
00:00:03.540 --> 00:00:05.650 A:middle L:90%
we want to sketch the graph of this function.
2
00:00:05.809 --> 00:00:08.699 A:middle L:90%
And so we should first think about its parent function
3
00:00:08.710 --> 00:00:11.570 A:middle L:90%
. Y equals the absolute value. Becks. Hopefully
4
00:00:11.570 --> 00:00:13.390 A:middle L:90%
, we have a feel for what that looks like
5
00:00:13.849 --> 00:00:15.970 A:middle L:90%
. That's going to be that V shaped graph,
6
00:00:15.980 --> 00:00:19.940 A:middle L:90%
which has a vertex at 00 and one line has
7
00:00:19.940 --> 00:00:21.550 A:middle L:90%
a slope of one. The other has a slope
8
00:00:21.550 --> 00:00:24.579 A:middle L:90%
of negative one. So then our function f of
9
00:00:24.579 --> 00:00:27.550 A:middle L:90%
X is going to be that function but translated to
10
00:00:27.550 --> 00:00:31.699 A:middle L:90%
the left to, and we can also find some
11
00:00:31.699 --> 00:00:35.789 A:middle L:90%
points to plot. The pivotal point will be where
12
00:00:35.789 --> 00:00:38.369 A:middle L:90%
the where we're taking the absolute value of zero,
13
00:00:38.380 --> 00:00:41.310 A:middle L:90%
and so that will be negative, too. If
14
00:00:41.310 --> 00:00:43.390 A:middle L:90%
you have X equals negative to the Y, value
15
00:00:43.390 --> 00:00:45.960 A:middle L:90%
will be zero. Now let's find the coordinates of
16
00:00:45.960 --> 00:00:47.960 A:middle L:90%
a couple points to the left of and to the
17
00:00:47.960 --> 00:00:50.320 A:middle L:90%
right of that. So to the left of that
18
00:00:50.320 --> 00:00:53.359 A:middle L:90%
, we could do negative three and negative four f
19
00:00:53.359 --> 00:00:55.850 A:middle L:90%
of negative three is one f of negative four is
20
00:00:55.850 --> 00:00:58.119 A:middle L:90%
, too. To the right of that, we
21
00:00:58.119 --> 00:01:00.399 A:middle L:90%
could do negative one and zero f of negative.
22
00:01:00.399 --> 00:01:03.950 A:middle L:90%
One is one N f of zero is, too
23
00:01:03.640 --> 00:01:06.349 A:middle L:90%
. So let's go ahead and plot those points.
24
00:01:07.090 --> 00:01:11.459 A:middle L:90%
So if negative to zero negative 31 negative four to
25
00:01:11.540 --> 00:01:19.189 A:middle L:90%
negative 11 and zero to and then we can connect
26
00:01:19.189 --> 00:01:23.439 A:middle L:90%
those. And we have that V shaped absolute value
27
00:01:23.439 --> A:middle L:90%
graph.