WEBVTT
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we're gonna simplify. See over D, divided by
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three. Race to the negative to power. So
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this negative too. We're going to distribute to the
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CD and 23 So we have C to the negative
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to power D to the negative to power and three
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to the negative to power. So to get rid
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of these negatives, what we have to do is
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we have to change the position of our CD and
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three. So if I put three on the top
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00:00:33.630 --> 00:00:35.869 A:middle L:90%
, that changes, it's signed, took positive.
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And if I put the c and D at the
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bottom, it changes their sign too positive so I
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00:00:42.670 --> 00:00:50.460 A:middle L:90%
can do three squared at the top over C squared
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times the square at the bottom. And I know
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00:00:53.929 --> 00:00:59.399 A:middle L:90%
three squared is nine and then c squared over d
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00:00:59.399 --> 00:01:02.340 A:middle L:90%
squared will stay the same at the bottom. So
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00:01:02.350 --> 00:01:03.620 A:middle L:90%
this is my expression simplified