WEBVTT
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we begin this question by noting that the weight off
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an object on the surface off Planet A is equal
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to the weight off that same object at the surface
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on the planet be therefore D A Times M is
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equals two g b times the same mass. M
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done by Simply find the masses. We get the
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following G eight Izzy Coaster G. We now remember
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that the surface gravity often object, is given by
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Newton's constant times. The mass off that object divided
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by the radio's squared off the subject. So this
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relation implies that G. Newton's constant times the mass
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off Planet A divided by the radios off Planet A
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squared is because to the new terms, constant times
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the mass off planet be divided by the radios off
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Planet B squared then as D is a constant,
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we can simplify it. So we got that.
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The mass of Planet A, divided by the radios
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off planet A squared is equal to the mass offline
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. It be divided by the radios off definitely squared
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. Then we can sand are a to the other
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side multiplying and n b to the other side dividing
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. So we got em a divided by m Be
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easy goes to our a squared divided by r B
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squared But we know this information. The mass off
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planet A is equals 262% The mass of planet be
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therefore M A divided by EMI is he goes to
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0.6 so 0.6 is equals. Two are a divided
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by RV squared then the Rachel are a divided by
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r B is equal to the square it off 0.6
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, which is approximately 0.77.