WEBVTT
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we know that the position vector off the center off
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Mars off the system off particles is given by the
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situation equation number one. Well, I indicates to
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the ice particle. We also know that the total
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momentum off a system off of particles equals it's total
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mass multiplied by the velocity off the center off mass
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. So we can write the second equation According to
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that and where the moment, um, off each
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individual particle is given by P I is a culture
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m I t. Now in the first case taking
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the origin at the center, off mass off the
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yellow card and plus X access directed towards the center
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off mass toe the rain card. So the position
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off each center off mass is X y. Is
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it called a zero and Excel is a call.
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Judy is a call to 40 m. I hope
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we have only X component. So applying equation going
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to the system off the two cars so we will
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get X C m is equal to m by x
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y plus m r x r upon mm bye plus
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m r. So now we plug our values for
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M by M. R. we why we are
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so we get Xia physical too. 1200 in 20
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plus 1800 plus into 40 upon 1200 plus 1800 so
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we will help eggs. C M is a culture
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24 major twin center off Mass. So the center
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off mass off the system off the two cars plays
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between the center off mass off the yellow car and
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the center off Mass off the red card, which
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is 24 m from the center off Mass off the
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yellow car. Now, in the next case,
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we plug our values for em by and Viv I
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into Equation three. That means in this situation the
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turban. So we relegate B Y is equal to
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1200 into 12 which is equivalent to 14400 kilogram into
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me. The 1st, 2nd and flubber values for
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Emma and we're into Equation three. So we'll get
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the mo mentum off R B R is equal to
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1802 20 equivalent to 36,000 kilogram into meter per second
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. So the total mo mentum off the system off
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the two cars is be total is a call to
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B Y plus B r and the some off this
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. 14,400 36,000. We'll give you the answer 50,400
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kilograms into meet up on second Now reading the whole
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system as a particle with total Mars and musical toe
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Mbai plus m r. We can get the velocity
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off the system by plugging our values toe be total
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and AM into equation three Sylvie gate P total is
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equal tomb 1200 plus 1800 into the S. Yeah
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, so from this we will get V s is
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equal tomb 16.8 m per second. The velocity of
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the system is 16.8 m per second, which is
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the velocity off its center off months. So we
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can write BCM is a call to 16.8 m per
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second. Now we plug our values off M and
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V C M into equation too. So the gate
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the total is a pool too 1200 plus 1800 into
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16.8, which gives the answer. 50,400 kilogram me
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joke was second, which is the same result as
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part me mhm