WEBVTT
1
00:00:00.540 --> 00:00:03.299 A:middle L:90%
we're asked to estimate the limit numerically. Let's so
2
00:00:03.299 --> 00:00:05.200 A:middle L:90%
let's go ahead and do that together. So the
3
00:00:05.200 --> 00:00:09.470 A:middle L:90%
first thing we're gonna do is apply the Hopi data
4
00:00:09.470 --> 00:00:12.050 A:middle L:90%
room or the hospital or whatever you want to say
5
00:00:12.439 --> 00:00:15.519 A:middle L:90%
. Which we can say that the limit as acts
6
00:00:15.519 --> 00:00:18.420 A:middle L:90%
approaches zero. Um, we can go ahead and
7
00:00:18.420 --> 00:00:22.550 A:middle L:90%
say that this is actually indeed negative Sign of X
8
00:00:23.140 --> 00:00:26.070 A:middle L:90%
all over one. So what we did is we
9
00:00:26.140 --> 00:00:28.480 A:middle L:90%
said that coastline of X minus one is in fact
10
00:00:28.489 --> 00:00:31.449 A:middle L:90%
, just a sign of our negative sign of X
11
00:00:31.449 --> 00:00:34.060 A:middle L:90%
. And then we replaced the ex with one on
12
00:00:34.060 --> 00:00:37.070 A:middle L:90%
the bottom so that we go ahead typify to the
13
00:00:37.070 --> 00:00:41.439 A:middle L:90%
limit as X approaches zero off the negative sign of
14
00:00:41.439 --> 00:00:43.429 A:middle L:90%
X. So we go ahead and get rid of
15
00:00:43.429 --> 00:00:45.840 A:middle L:90%
this one of the bottom. Now we're gonna go
16
00:00:45.840 --> 00:00:47.679 A:middle L:90%
ahead and plug in. The value of X equal
17
00:00:47.679 --> 00:00:52.359 A:middle L:90%
is zero right here. So the sign of zero
18
00:00:52.450 --> 00:00:58.350 A:middle L:90%
is indeed zero. So this turns into zero.
19
00:00:58.840 --> 00:00:59.950 A:middle L:90%
Our answer is zero