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uh this problem is actually doable. Um You just
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need a lot of practice to recognize a pattern like
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this. And I don't have good advice other than
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to know your trig identities. Um And the reason
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why is a I'm gonna rewrite tangent squared with what
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it's equal to and one of the trig identities I'm
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talking about is uh Mhm tangent squared of theta Plus
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one is equal to seek and squared of data.
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So by doing a little algebra manipulation, I'm going
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to leave most of this alone. I may replace
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tangent squared, switch over to read to seek and
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squared And subtract one over. Uh mentally that in
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black and you might be sitting there saying why on
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earth would you do that? Well now we can
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combine like terms to be one plus second squared of
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data. D theta And the reason why that's to
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your benefits when with data being your independent variable,
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then the anti derivative of one would just be data
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Because the drift of the state will be one.
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And I'm thinking about the derivative of something that equal
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second squared. And that answer is tangent of state
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is directive is seeking squared, and then you just
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need to remember to add your constant plus C.
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You have the correct answer. Mhm.