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All right, so four problem 40 45 A function
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is given by acti, which is equal to 12
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. T minus three t Sorry. He's t cute
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. Too cute and domain of dysfunction is from negative
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three to infinity. Okay, Now, for part
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of it, all this problem when you take the
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directive of this function. So it gives 12 miners
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three t squared and we let this the real due
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to be zero than we have t squared is equal
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to four. And so t could be positive or
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negative too. All right, so these are our
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local extremes already down to and have a collective too
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. So to check whether these two batters are absolute
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extreme. Um, if we check the shape of
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this function, that is, then we need to
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find out the increase interval and decreasing Devo. So
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the directive is minus read. He's weird. We
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let this to be positive then that gives t squared
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smaller than T. C squared is smaller than four
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. So our tea will be from negative to two
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. Positive too. So that means on this interval
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already, function will be increasing and from connecting affinity
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to elected to union to infinity or function will be
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decreasing. So our grab up the function will be
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like this neck of two and two on from 19
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infinity and connected to this sissy decreasing. And then
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it is increasing and it is decreasing. So from
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Margraff, we can definitely see dead. No,
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these now all these local extremes are the absolute extremes
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. So No, no, no are absolute.
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Or now them is absent, okay?